Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 100 m14 m/sF = ?

A 900 kg car drives around a flat curve of radius 100 m at a constant 14 m/s. Find the inward (centripetal) force Fc needed.

m = 900 kgv = 14 m/sr = 100 m
Fc = N
2.Easy
r = 0.95 mv = ?90 rpm

A small object sits 95 cm from the axis of a disc that turns at a steady 90 revolutions per minute. Find the speed v of the object.

n = 90 rpmr = 0.95 m
v = m/s
3.Medium
L = 2 m30°

A small ball on a string of length 2 m moves in a horizontal circle so that the string makes a constant angle of 30° with the vertical (a conical pendulum). Use g = 9.81 m/s². Find the speed v of the ball.

L = 2 mθ = 30°g = 9.81 m/s²
v = m/s
4.Medium
L = 2 m30°

A small ball on a string of length 2 m moves in a horizontal circle so that the string makes a constant angle of 30° with the vertical (a conical pendulum). Use g = 9.81 m/s². Find the time T for one revolution.

L = 2 mθ = 30°g = 9.81 m/s²
T = s
5.Hard
r = 1.4 mv = 5 m/s

A 1.2 kg ball on a string 1.4 m long is swung in a vertical circle. At the lowest point it moves at 5 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 1.2 kgr = 1.4 mv = 5 m/sg = 9.81 m/s²
T = N
6.Hard
θ = 20°to centrevmax​ = ?

A curve of radius 160 m is banked at 20°, and the coefficient of static friction between tyres and road is 0.1. Use g = 9.81 m/s². Find the highest speed vmax at which a car can take the curve without sliding up and out.

r = 160 mθ = 20°μs = 0.1g = 9.81 m/s²
vmax = m/s

Answer key

  1. 1. Fc = 1764 N
  2. 2. v = 8.954 m/s
  3. 3. v = 2.38 m/s
  4. 4. T = 2.64 s
  5. 5. T = 33.2 N
  6. 6. vmax = 27.49 m/s

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