Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 150 m9 m/sac​ = ?

A 1800 kg car drives around a flat curve of radius 150 m at a constant 9 m/s. Find its centripetal acceleration ac.

m = 1800 kgv = 9 m/sr = 150 m
ac = m/s²
2.Easy
r = 1.6 mvmax​ = ?

A 0.7 kg stone is whirled in a horizontal circle of radius 1.6 m on a smooth, level table, held by a string that breaks at a tension of 120 N. Find the highest speed vmax the stone can have.

m = 0.7 kgr = 1.6 mTmax = 120 N
vmax = m/s
3.Medium
r = 105 mvmax​ = ?

A car takes a flat curve of radius 105 m. The coefficient of static friction between tyres and road is 0.4. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 105 mμs = 0.4g = 9.81 m/s²
vmax = m/s
4.Medium
r = 110 mvmax​ = ?

A car takes a flat curve of radius 110 m. The coefficient of static friction between tyres and road is 0.8. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 110 mμs = 0.8g = 9.81 m/s²
vmax = m/s
5.Hard
r = 1.2 mv = ?

A ball on a string 1.2 m long is swung in a vertical circle. Use g = 9.81 m/s². What is the smallest speed vmin at the top for which the string just stays tight?

r = 1.2 mg = 9.81 m/s²
vmin = m/s
6.Hard
r = 1.3 mv = 7.5 m/s

A 1.7 kg ball on a string 1.3 m long is swung in a vertical circle. At the lowest point it moves at 7.5 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 1.7 kgr = 1.3 mv = 7.5 m/sg = 9.81 m/s²
T = N

Answer key

  1. 1. ac = 0.54 m/s²
  2. 2. vmax = 16.56 m/s
  3. 3. vmax = 20.3 m/s
  4. 4. vmax = 29.38 m/s
  5. 5. vmin = 3.431 m/s
  6. 6. T = 90.23 N

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