Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
r = 0.65 mv120 rpm

A small object sits 65 cm from the axis of a disc that turns at a steady 120 revolutions per minute. Find its centripetal acceleration ac.

n = 120 rpmr = 0.65 m
ac = m/s²
2.Easy
r = 200 m26 m/sF = ?

A 1100 kg car drives around a flat curve of radius 200 m at a constant 26 m/s. Find the inward (centripetal) force Fc needed.

m = 1100 kgv = 26 m/sr = 200 m
Fc = N
3.Medium
r = 30 mvmax​ = ?

A car takes a flat curve of radius 30 m. The coefficient of static friction between tyres and road is 0.3. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 30 mμs = 0.3g = 9.81 m/s²
vmax = m/s
4.Medium
r = 95 mvmax​ = ?

A car takes a flat curve of radius 95 m. The coefficient of static friction between tyres and road is 0.5. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 95 mμs = 0.5g = 9.81 m/s²
vmax = m/s
5.Hard
r = 1.1 mv = ?

A ball on a string 1.1 m long is swung in a vertical circle. Use g = 9.81 m/s². What is the smallest speed vmin at the top for which the string just stays tight?

r = 1.1 mg = 9.81 m/s²
vmin = m/s
6.Hard
R = 1.5 mh = ?

A small cart is released from rest on a frictionless track and runs into a vertical loop of radius 1.5 m. From what minimum height hmin above the bottom of the loop must it start to stay on the track at the top of the loop?

R = 1.5 mv₀ = 0
hmin = m

Answer key

  1. 1. ac = 102.6 m/s²
  2. 2. Fc = 3718 N
  3. 3. vmax = 9.396 m/s
  4. 4. vmax = 21.59 m/s
  5. 5. vmin = 3.285 m/s
  6. 6. hmin = 3.75 m

Full step-by-step solutions: practise this topic on examproblems.com.