1.Easy
A 0.9 kg stone is whirled in a horizontal circle of radius 1 m on a smooth, level table, held by a string that breaks at a tension of 110 N. Find the highest speed vmax the stone can have.
m = 0.9 kgr = 1 mTmax = 110 N
vmax = m/s
Circular motion worksheet with answers
2.Easy
A small object sits 35 cm from the axis of a disc that turns at a steady 30 revolutions per minute. Find the speed v of the object.
n = 30 rpmr = 0.35 m
v = m/s
3.Medium
A car takes a flat curve of radius 25 m. The coefficient of static friction between tyres and road is 0.5. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.
r = 25 mμs = 0.5g = 9.81 m/s²
vmax = m/s
4.Medium
A car takes a flat curve of radius 95 m. The coefficient of static friction between tyres and road is 0.7. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.
r = 95 mμs = 0.7g = 9.81 m/s²
vmax = m/s
5.Hard
A 1.6 kg ball on a light string 1 m long is swung in a vertical circle. At the lowest point its speed is 10 m/s. Ignore air resistance and use g = 9.81 m/s². Find the tension Ttop in the string at the highest point.
m = 1.6 kgr = 1 mvbottom = 10 m/sg = 9.81 m/s²
Ttop = N
6.Hard
A curve of radius 80 m is banked at 10°, and the coefficient of static friction between tyres and road is 0.4. Use g = 9.81 m/s². Find the highest speed vmax at which a car can take the curve without sliding up and out.
r = 80 mθ = 10°μs = 0.4g = 9.81 m/s²
vmax = m/s
Answer key
- 1. vmax = 11.06 m/s
- 2. v = 1.1 m/s
- 3. vmax = 11.07 m/s
- 4. vmax = 25.54 m/s
- 5. Ttop = 81.52 N
- 6. vmax = 22.06 m/s
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