Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 40 m28 m/sac​ = ?

A 600 kg car drives around a flat curve of radius 40 m at a constant 28 m/s. Find its centripetal acceleration ac.

m = 600 kgv = 28 m/sr = 40 m
ac = m/s²
2.Easy
r = ?240 km/h

For passenger comfort the centripetal acceleration on a railway curve must not exceed 1 m/s². What is the smallest radius rmin for a curve taken at 240 km/h?

v = 240 km/hamax = 1 m/s²
rmin = m
3.Medium
r = 75 mvmax​ = ?

A car takes a flat curve of radius 75 m. The coefficient of static friction between tyres and road is 0.8. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 75 mμs = 0.8g = 9.81 m/s²
vmax = m/s
4.Medium
r = 1.8 mn = ?

In a fairground rotor, riders stand against the wall of a vertical cylinder of radius 1.8 m. When it spins fast enough the floor drops away and friction holds them up. The coefficient of static friction is 0.8. Use g = 9.81 m/s². Find the smallest rotation rate n in revolutions per minute.

r = 1.8 mμs = 0.8g = 9.81 m/s²
n = rpm
5.Hard
r = 1.2 mv = ?

A ball on a string 1.2 m long is swung in a vertical circle. Use g = 9.81 m/s². What is the smallest speed vmin at the top for which the string just stays tight?

r = 1.2 mg = 9.81 m/s²
vmin = m/s
6.Hard
r = 1.2 mv = 9 m/s

A 0.9 kg ball on a string 1.2 m long is swung in a vertical circle. At the lowest point it moves at 9 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 0.9 kgr = 1.2 mv = 9 m/sg = 9.81 m/s²
T = N

Answer key

  1. 1. ac = 19.6 m/s²
  2. 2. rmin = 4444 m
  3. 3. vmax = 24.26 m/s
  4. 4. n = 24.92 rpm
  5. 5. vmin = 3.431 m/s
  6. 6. T = 69.58 N

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