Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 70 m23 m/sF = ?

A 1500 kg car drives around a flat curve of radius 70 m at a constant 23 m/s. Find the inward (centripetal) force Fc needed.

m = 1500 kgv = 23 m/sr = 70 m
Fc = N
2.Easy
r = 1.1 mvmax​ = ?

A 0.8 kg stone is whirled in a horizontal circle of radius 1.1 m on a smooth, level table, held by a string that breaks at a tension of 60 N. Find the highest speed vmax the stone can have.

m = 0.8 kgr = 1.1 mTmax = 60 N
vmax = m/s
3.Medium
r = 25 m7 m/s

A 1500 kg car drives over the top of a hump in the road at 7 m/s. The top of the hump is a circular arc of radius 25 m. Use g = 9.81 m/s². Find the normal force N of the road on the car at the top.

m = 1500 kgv = 7 m/sr = 25 mg = 9.81 m/s²
N = N
4.Medium
r = 65 mvmax​ = ?

A car takes a flat curve of radius 65 m. The coefficient of static friction between tyres and road is 0.4. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 65 mμs = 0.4g = 9.81 m/s²
vmax = m/s
5.Hard
r = 0.7 mv = ?

A ball on a string 0.7 m long is swung in a vertical circle. Use g = 9.81 m/s². What is the smallest speed vmin at the top for which the string just stays tight?

r = 0.7 mg = 9.81 m/s²
vmin = m/s
6.Hard
r = 1.5 mv = ?

A ball on a string 1.5 m long is swung in a vertical circle. Use g = 9.81 m/s². What is the smallest speed vmin at the top for which the string just stays tight?

r = 1.5 mg = 9.81 m/s²
vmin = m/s

Answer key

  1. 1. Fc = 11336 N
  2. 2. vmax = 9.083 m/s
  3. 3. N = 11775 N
  4. 4. vmax = 15.97 m/s
  5. 5. vmin = 2.62 m/s
  6. 6. vmin = 3.836 m/s

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