Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 160 m9 m/sF = ?

A 600 kg car drives around a flat curve of radius 160 m at a constant 9 m/s. Find the inward (centripetal) force Fc needed.

m = 600 kgv = 9 m/sr = 160 m
Fc = N
2.Easy
r = 150 m24 m/sac​ = ?

A 1700 kg car drives around a flat curve of radius 150 m at a constant 24 m/s. Find its centripetal acceleration ac.

m = 1700 kgv = 24 m/sr = 150 m
ac = m/s²
3.Medium
r = 50 mvmax​ = ?

A car takes a flat curve of radius 50 m. The coefficient of static friction between tyres and road is 0.8. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 50 mμs = 0.8g = 9.81 m/s²
vmax = m/s
4.Medium
r = 145 mvmax​ = ?

A car takes a flat curve of radius 145 m. The coefficient of static friction between tyres and road is 0.5. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 145 mμs = 0.5g = 9.81 m/s²
vmax = m/s
5.Hard
r = 1.5 mv = 4 m/s

A 1.7 kg ball on a string 1.5 m long is swung in a vertical circle. At the lowest point it moves at 4 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 1.7 kgr = 1.5 mv = 4 m/sg = 9.81 m/s²
T = N
6.Hard
r = 1.5 mv = 5.5 m/s

A 1.9 kg ball on a string 1.5 m long is swung in a vertical circle. At the lowest point it moves at 5.5 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 1.9 kgr = 1.5 mv = 5.5 m/sg = 9.81 m/s²
T = N

Answer key

  1. 1. Fc = 303.8 N
  2. 2. ac = 3.84 m/s²
  3. 3. vmax = 19.81 m/s
  4. 4. vmax = 26.67 m/s
  5. 5. T = 34.81 N
  6. 6. T = 56.96 N

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