Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
r = 160 m18 m/sac​ = ?

A 1000 kg car drives around a flat curve of radius 160 m at a constant 18 m/s. Find its centripetal acceleration ac.

m = 1000 kgv = 18 m/sr = 160 m
ac = m/s²
2.Easy
r = ?160 km/h

For passenger comfort the centripetal acceleration on a railway curve must not exceed 1.5 m/s². What is the smallest radius rmin for a curve taken at 160 km/h?

v = 160 km/hamax = 1.5 m/s²
rmin = m
3.Medium
r = 90 mvmax​ = ?

A car takes a flat curve of radius 90 m. The coefficient of static friction between tyres and road is 0.7. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 90 mμs = 0.7g = 9.81 m/s²
vmax = m/s
4.Medium
r = 65 mvmax​ = ?

A car takes a flat curve of radius 65 m. The coefficient of static friction between tyres and road is 0.3. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 65 mμs = 0.3g = 9.81 m/s²
vmax = m/s
5.Hard
θ = 15°to centrevmax​ = ?

A curve of radius 50 m is banked at 15°, and the coefficient of static friction between tyres and road is 0.15. Use g = 9.81 m/s². Find the highest speed vmax at which a car can take the curve without sliding up and out.

r = 50 mθ = 15°μs = 0.15g = 9.81 m/s²
vmax = m/s
6.Hard
r = 0.5 mv = ?

A ball on a string 0.5 m long is swung in a vertical circle. Use g = 9.81 m/s². What is the smallest speed vmin at the top for which the string just stays tight?

r = 0.5 mg = 9.81 m/s²
vmin = m/s

Answer key

  1. 1. ac = 2.025 m/s²
  2. 2. rmin = 1317 m
  3. 3. vmax = 24.86 m/s
  4. 4. vmax = 13.83 m/s
  5. 5. vmax = 14.61 m/s
  6. 6. vmin = 2.215 m/s

Full step-by-step solutions: practise this topic on examproblems.com.