Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 150 m29 m/sac​ = ?

A 900 kg car drives around a flat curve of radius 150 m at a constant 29 m/s. Find its centripetal acceleration ac.

m = 900 kgv = 29 m/sr = 150 m
ac = m/s²
2.Easy
r = ?200 km/h

For passenger comfort the centripetal acceleration on a railway curve must not exceed 1.5 m/s². What is the smallest radius rmin for a curve taken at 200 km/h?

v = 200 km/hamax = 1.5 m/s²
rmin = m
3.Medium
L = 1.7 m60°

A small ball on a string of length 1.7 m moves in a horizontal circle so that the string makes a constant angle of 60° with the vertical (a conical pendulum). Use g = 9.81 m/s². Find the speed v of the ball.

L = 1.7 mθ = 60°g = 9.81 m/s²
v = m/s
4.Medium
L = 0.7 m30°

A small ball on a string of length 0.7 m moves in a horizontal circle so that the string makes a constant angle of 30° with the vertical (a conical pendulum). Use g = 9.81 m/s². Find the speed v of the ball.

L = 0.7 mθ = 30°g = 9.81 m/s²
v = m/s
5.Hard
θ = 30°to centrevmax​ = ?

A curve of radius 40 m is banked at 30°, and the coefficient of static friction between tyres and road is 0.15. Use g = 9.81 m/s². Find the highest speed vmax at which a car can take the curve without sliding up and out.

r = 40 mθ = 30°μs = 0.15g = 9.81 m/s²
vmax = m/s
6.Hard
r = 0.5 mv = ?

A ball on a string 0.5 m long is swung in a vertical circle. Use g = 9.81 m/s². What is the smallest speed vmin at the top for which the string just stays tight?

r = 0.5 mg = 9.81 m/s²
vmin = m/s

Answer key

  1. 1. ac = 5.607 m/s²
  2. 2. rmin = 2058 m
  3. 3. v = 5.002 m/s
  4. 4. v = 1.408 m/s
  5. 5. vmax = 17.68 m/s
  6. 6. vmin = 2.215 m/s

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