Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 190 m21 m/sF = ?

A 1800 kg car drives around a flat curve of radius 190 m at a constant 21 m/s. Find the inward (centripetal) force Fc needed.

m = 1800 kgv = 21 m/sr = 190 m
Fc = N
2.Easy
r = 20 m24 m/sac​ = ?

A 1400 kg car drives around a flat curve of radius 20 m at a constant 24 m/s. Find its centripetal acceleration ac.

m = 1400 kgv = 24 m/sr = 20 m
ac = m/s²
3.Medium
r = 60 mvmax​ = ?

A car takes a flat curve of radius 60 m. The coefficient of static friction between tyres and road is 0.3. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 60 mμs = 0.3g = 9.81 m/s²
vmax = m/s
4.Medium
r = 135 mvmax​ = ?

A car takes a flat curve of radius 135 m. The coefficient of static friction between tyres and road is 0.5. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 135 mμs = 0.5g = 9.81 m/s²
vmax = m/s
5.Hard
θ = 10°to centrevmax​ = ?

A curve of radius 260 m is banked at 10°, and the coefficient of static friction between tyres and road is 0.15. Use g = 9.81 m/s². Find the highest speed vmax at which a car can take the curve without sliding up and out.

r = 260 mθ = 10°μs = 0.15g = 9.81 m/s²
vmax = m/s
6.Hard
r = 1 mv = 4 m/s

A 1.1 kg ball on a string 1 m long is swung in a vertical circle. At the lowest point it moves at 4 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 1.1 kgr = 1 mv = 4 m/sg = 9.81 m/s²
T = N

Answer key

  1. 1. Fc = 4178 N
  2. 2. ac = 28.8 m/s²
  3. 3. vmax = 13.29 m/s
  4. 4. vmax = 25.73 m/s
  5. 5. vmax = 29.24 m/s
  6. 6. T = 28.39 N

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