Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
r = 90 m17 m/sac​ = ?

A 700 kg car drives around a flat curve of radius 90 m at a constant 17 m/s. Find its centripetal acceleration ac.

m = 700 kgv = 17 m/sr = 90 m
ac = m/s²
2.Easy
r = 1.9 mvmax​ = ?

A 1.1 kg stone is whirled in a horizontal circle of radius 1.9 m on a smooth, level table, held by a string that breaks at a tension of 20 N. Find the highest speed vmax the stone can have.

m = 1.1 kgr = 1.9 mTmax = 20 N
vmax = m/s
3.Medium
r = 95 mvmax​ = ?

A car takes a flat curve of radius 95 m. The coefficient of static friction between tyres and road is 0.3. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 95 mμs = 0.3g = 9.81 m/s²
vmax = m/s
4.Medium
r = 50 mvmax​ = ?

A car drives over the top of a hump in the road, which is a circular arc of radius 50 m. Use g = 9.81 m/s². Above what speed vmax do the wheels leave the road at the top?

r = 50 mg = 9.81 m/s²
vmax = m/s
5.Hard
r = 1.2 mv = 6.5 m/s

A 1.3 kg ball on a string 1.2 m long is swung in a vertical circle. At the lowest point it moves at 6.5 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 1.3 kgr = 1.2 mv = 6.5 m/sg = 9.81 m/s²
T = N
6.Hard
r = 0.6 mv = ?

A ball on a string 0.6 m long is swung in a vertical circle. Use g = 9.81 m/s². What is the smallest speed vmin at the top for which the string just stays tight?

r = 0.6 mg = 9.81 m/s²
vmin = m/s

Answer key

  1. 1. ac = 3.211 m/s²
  2. 2. vmax = 5.878 m/s
  3. 3. vmax = 16.72 m/s
  4. 4. vmax = 22.15 m/s
  5. 5. T = 58.52 N
  6. 6. vmin = 2.426 m/s

Full step-by-step solutions: practise this topic on examproblems.com.