Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 160 m18 m/sF = ?

A 700 kg car drives around a flat curve of radius 160 m at a constant 18 m/s. Find the inward (centripetal) force Fc needed.

m = 700 kgv = 18 m/sr = 160 m
Fc = N
2.Easy
r = ?240 km/h

For passenger comfort the centripetal acceleration on a railway curve must not exceed 1.2 m/s². What is the smallest radius rmin for a curve taken at 240 km/h?

v = 240 km/hamax = 1.2 m/s²
rmin = m
3.Medium
L = 1.9 m30°

A small ball on a string of length 1.9 m moves in a horizontal circle so that the string makes a constant angle of 30° with the vertical (a conical pendulum). Use g = 9.81 m/s². Find the time T for one revolution.

L = 1.9 mθ = 30°g = 9.81 m/s²
T = s
4.Medium
θ = ?to centre90 km/h

A road engineer wants cars to take a curve of radius 170 m at 90 km/h without relying on friction. Use g = 9.81 m/s². Find the banking angle θ.

r = 170 mv = 90 km/hg = 9.81 m/s²
θ = °
5.Hard
r = 0.9 m10 m/svtop​ = ?

A 2 kg ball on a light string 0.9 m long is swung in a vertical circle. At the lowest point its speed is 10 m/s. Ignore air resistance and use g = 9.81 m/s². Find the tension Ttop in the string at the highest point.

m = 2 kgr = 0.9 mvbottom = 10 m/sg = 9.81 m/s²
Ttop = N
6.Hard
r = 0.9 mv = 4 m/s

A 1.6 kg ball on a string 0.9 m long is swung in a vertical circle. At the lowest point it moves at 4 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 1.6 kgr = 0.9 mv = 4 m/sg = 9.81 m/s²
T = N

Answer key

  1. 1. Fc = 1418 N
  2. 2. rmin = 3704 m
  3. 3. T = 2.573 s
  4. 4. θ = 20.54 °
  5. 5. Ttop = 124.1 N
  6. 6. T = 44.14 N

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