Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = ?240 km/h

For passenger comfort the centripetal acceleration on a railway curve must not exceed 1 m/s². What is the smallest radius rmin for a curve taken at 240 km/h?

v = 240 km/hamax = 1 m/s²
rmin = m
2.Easy
r = 100 m17 m/sF = ?

A 1600 kg car drives around a flat curve of radius 100 m at a constant 17 m/s. Find the inward (centripetal) force Fc needed.

m = 1600 kgv = 17 m/sr = 100 m
Fc = N
3.Medium
θ = 15°to centrev = ?

A curve of radius 100 m is banked at 15°. At what speed v can a car take it with no friction needed at all? Use g = 9.81 m/s².

r = 100 mθ = 15°g = 9.81 m/s²
v = m/s
4.Medium
r = 2.9 mn = ?

In a fairground rotor, riders stand against the wall of a vertical cylinder of radius 2.9 m. When it spins fast enough the floor drops away and friction holds them up. The coefficient of static friction is 0.4. Use g = 9.81 m/s². Find the smallest rotation rate n in revolutions per minute.

r = 2.9 mμs = 0.4g = 9.81 m/s²
n = rpm
5.Hard
r = 1.1 mv = ?

A ball on a string 1.1 m long is swung in a vertical circle. Use g = 9.81 m/s². What is the smallest speed vmin at the top for which the string just stays tight?

r = 1.1 mg = 9.81 m/s²
vmin = m/s
6.Hard
r = 1.3 m11 m/svtop​ = ?

A 1.6 kg ball on a light string 1.3 m long is swung in a vertical circle. At the lowest point its speed is 11 m/s. Ignore air resistance and use g = 9.81 m/s². Find the tension Ttop in the string at the highest point.

m = 1.6 kgr = 1.3 mvbottom = 11 m/sg = 9.81 m/s²
Ttop = N

Answer key

  1. 1. rmin = 4444 m
  2. 2. Fc = 4624 N
  3. 3. v = 16.21 m/s
  4. 4. n = 27.77 rpm
  5. 5. vmin = 3.285 m/s
  6. 6. Ttop = 70.44 N

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