Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 1.7 mvmax​ = ?

A 1.1 kg stone is whirled in a horizontal circle of radius 1.7 m on a smooth, level table, held by a string that breaks at a tension of 80 N. Find the highest speed vmax the stone can have.

m = 1.1 kgr = 1.7 mTmax = 80 N
vmax = m/s
2.Easy
r = 200 m10 m/sF = ?

A 600 kg car drives around a flat curve of radius 200 m at a constant 10 m/s. Find the inward (centripetal) force Fc needed.

m = 600 kgv = 10 m/sr = 200 m
Fc = N
3.Medium
θ = ?to centre70 km/h

A road engineer wants cars to take a curve of radius 270 m at 70 km/h without relying on friction. Use g = 9.81 m/s². Find the banking angle θ.

r = 270 mv = 70 km/hg = 9.81 m/s²
θ = °
4.Medium
r = 55 mvmax​ = ?

A car takes a flat curve of radius 55 m. The coefficient of static friction between tyres and road is 0.5. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 55 mμs = 0.5g = 9.81 m/s²
vmax = m/s
5.Hard
θ = 15°to centrevmin​ = ?

A curve of radius 60 m is banked at 15°, and the coefficient of static friction between tyres and road is 0.1. Use g = 9.81 m/s². Find the lowest speed vmin at which a car can take the curve without sliding down the bank.

r = 60 mθ = 15°μs = 0.1g = 9.81 m/s²
vmin = m/s
6.Hard
r = 0.5 mv = 9 m/s

A 0.4 kg ball on a string 0.5 m long is swung in a vertical circle. At the lowest point it moves at 9 m/s. Use g = 9.81 m/s². Find the tension T in the string at the lowest point.

m = 0.4 kgr = 0.5 mv = 9 m/sg = 9.81 m/s²
T = N

Answer key

  1. 1. vmax = 11.12 m/s
  2. 2. Fc = 300 N
  3. 3. θ = 8.124 °
  4. 4. vmax = 16.42 m/s
  5. 5. vmin = 9.812 m/s
  6. 6. T = 68.72 N

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