Circular motion worksheet with answers

Free printable Circular motion worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
r = 150 m27 m/sac​ = ?

A 900 kg car drives around a flat curve of radius 150 m at a constant 27 m/s. Find its centripetal acceleration ac.

m = 900 kgv = 27 m/sr = 150 m
ac = m/s²
2.Easy
r = 80 m10 m/sF = ?

A 1800 kg car drives around a flat curve of radius 80 m at a constant 10 m/s. Find the inward (centripetal) force Fc needed.

m = 1800 kgv = 10 m/sr = 80 m
Fc = N
3.Medium
θ = ?to centre80 km/h

A road engineer wants cars to take a curve of radius 150 m at 80 km/h without relying on friction. Use g = 9.81 m/s². Find the banking angle θ.

r = 150 mv = 80 km/hg = 9.81 m/s²
θ = °
4.Medium
r = 85 mvmax​ = ?

A car takes a flat curve of radius 85 m. The coefficient of static friction between tyres and road is 0.5. Use g = 9.81 m/s². Find the highest speed vmax at which the car can take the curve without skidding.

r = 85 mμs = 0.5g = 9.81 m/s²
vmax = m/s
5.Hard
θ = 30°to centrevmin​ = ?

A curve of radius 250 m is banked at 30°, and the coefficient of static friction between tyres and road is 0.3. Use g = 9.81 m/s². Find the lowest speed vmin at which a car can take the curve without sliding down the bank.

r = 250 mθ = 30°μs = 0.3g = 9.81 m/s²
vmin = m/s
6.Hard
R = 9.5 mh = 45.6 m

A 2.5 kg cart is released from rest at a height of 45.6 m on a frictionless track and runs through a vertical loop of radius 9.5 m. Use g = 9.81 m/s². Find the normal force Nbottom of the track on the cart at the bottom of the loop.

m = 2.5 kgh = 45.6 mR = 9.5 mg = 9.81 m/s²
Nbottom = N

Answer key

  1. 1. ac = 4.86 m/s²
  2. 2. Fc = 2250 N
  3. 3. θ = 18.55 °
  4. 4. vmax = 20.42 m/s
  5. 5. vmin = 24.08 m/s
  6. 6. Nbottom = 260 N

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