Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Vd = 0.7 L/kgC = 25 mg/LLD = ?78 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 78 kg needs a loading dose of vancomycin to reach a level of 25 mg/L straight away. The volume of distribution is 0.7 L/kg. Find the loading dose LD in mg.

78 kgVd = 0.7 L/kgC = 25 mg/L
LD = mg
2.Easy
Vd = 0.5 L/kgC = 12 mg/LLD = ?60 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 60 kg needs a loading dose of theophylline to reach a level of 12 mg/L straight away. The volume of distribution is 0.5 L/kg. Find the loading dose LD in mg.

60 kgVd = 0.5 L/kgC = 12 mg/L
LD = mg
3.Medium
110100t (h)C (mg/L)1 h10 mg/L4 h3.5 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 10 mg/L at 1 h and 3.5 mg/L at 4 h. Assume first-order elimination. Find the half-life t½.

C1 = 10 mg/L (1 h)C2 = 3.5 mg/L (4 h)
t½ = h
4.Medium
VCss​ = 12 mg/LR = ? mg/hCL = 0.04 L/kg/h96 kg

Practice exercise (made-up values, not clinical guidance). A 96 kg patient receives a theophylline infusion. The clearance is 0.04 L/kg/h. What infusion rate R in mg/h gives a steady-state level of 12 mg/L?

96 kgCL = 0.04 L/kg/hCss = 12 mg/L
R = mg/h
5.Hard
VCss,avg​ = 25 mg/LD = ? mg · q12hCL = 3 L/hS = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A patient receives vancomycin IV every 12 h; the vancomycin clearance is 3 L/h. What dose D in mg gives an average steady-state level of 25 mg/L?

CL = 3 L/hτ = 12 hS = 1F = 1Css,avg = 25 mg/L
D = mg
6.Hard
Vd = 0.25 L/kg0.5 → 8 mg/LD = ? mg89 kg

Practice exercise (made-up values, not clinical guidance). An 89 kg patient on regular tobramycin doses is at steady state. The target is a peak of 8 mg/L and a trough of 0.5 mg/L, and the volume of distribution is 0.25 L/kg. Assuming rapid IV doses, what dose D raises the level from the trough to the peak?

89 kgVd = 0.25 L/kgCpeak = 8 mg/LCtrough = 0.5 mg/L
D = mg

Answer key

  1. 1. LD = 1365 mg
  2. 2. LD = 360 mg
  3. 3. t½ = 1.981 h
  4. 4. R = 46.08 mg/h
  5. 5. D = 900 mg
  6. 6. D = 166.9 mg

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