Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

New worksheetPractise online with hints

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
110100t (h)CC₀t½ = 3 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, tobramycin has an elimination half-life of 3 h. Find the elimination rate constant k in h⁻¹.

t½ = 3 h
k = h⁻¹
2.Easy
110t (h)C (mg/L)6 mg/L2.5 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the tobramycin level is 6 mg/L. The half-life is 2.5 h, and the drug is eliminated by first-order kinetics. What is the level C 2.5 h later?

C₀ = 6 mg/Lt½ = 2.5 ht = 2.5 h
C = mg/L
3.Medium
Vd = 0.5 L/kgC = 15 mg/LLD = ? mg50 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 50 kg patient is to be loaded intravenously with aminophylline to reach a theophylline level of 15 mg/L. The volume of distribution is 0.5 L/kg and the salt factor is S = 0.8. Find the loading dose LD of aminophylline in mg.

50 kgVd = 0.5 L/kgC = 15 mg/LS = 0.8
LD = mg
4.Medium
Vd = 0.5 L/kgC = 10 mg/LLD = ? mg97 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 97 kg patient is to be loaded intravenously with aminophylline to reach a theophylline level of 10 mg/L. The volume of distribution is 0.5 L/kg and the salt factor is S = 0.8. Find the loading dose LD of aminophylline in mg.

97 kgVd = 0.5 L/kgC = 10 mg/LS = 0.8
LD = mg
5.Hard
t (h)C (mg/L)Css​7 hC = ?

Practice exercise (made-up values, not clinical guidance). A vancomycin infusion runs at 80 mg/h with no loading dose. The patient's clearance is 4 L/h and the half-life is 10 h. What is the level C after 7 h?

R = 80 mg/hCL = 4 L/ht½ = 10 ht = 7 h
C = mg/L
6.Hard
VCss,avg​ = ?400 mg · q12hCL = 0.04 L/kg/h68 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A 68 kg patient takes oral theophylline (F = 1) every 12 h. The clearance is 0.04 L/kg/h. Each dose is 400 mg of theophylline. Find the average steady-state level Css,avg.

CL = 0.04 L/kg/hτ = 12 hS = 1F = 168 kgD = 400 mg
Css,avg = mg/L

Answer key

  1. 1. k = 0.231 h⁻¹
  2. 2. C = 3 mg/L
  3. 3. LD = 468.8 mg
  4. 4. LD = 606.3 mg
  5. 5. C = 7.689 mg/L
  6. 6. Css,avg = 12.25 mg/L

Full step-by-step solutions: practise this topic on examproblems.com.