Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)C (mg/L)35 mg/L27 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 35 mg/L. The half-life is 9 h, and the drug is eliminated by first-order kinetics. What is the level C 27 h later?

C₀ = 35 mg/Lt½ = 9 ht = 27 h
C = mg/L
2.Easy
t/t½C/Css (%)100%597%

Practice exercise (made-up values, not clinical guidance). A patient starts regular doses of vancomycin, which has a half-life of 10 h. Using the rule that steady state is reached after about five half-lives, after how many hours tss is steady state reached?

t½ = 10 h
tss = h
3.Medium
Vd = 0.5 L/kgC = 15 mg/LLD = ? mg91 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 91 kg patient is to be loaded intravenously with aminophylline to reach a theophylline level of 15 mg/L. The volume of distribution is 0.5 L/kg and the salt factor is S = 0.8. Find the loading dose LD of aminophylline in mg.

91 kgVd = 0.5 L/kgC = 15 mg/LS = 0.8
LD = mg
4.Medium
VCss​ = 25 mg/LR = ? mg/hCL = 70 mL/min

Practice exercise (made-up values, not clinical guidance). Vancomycin is given as a continuous infusion to a patient whose vancomycin clearance is 70 mL/min. What infusion rate R in mg/h gives a steady-state level of 25 mg/L?

CL = 70 mL/minCss = 25 mg/L
R = mg/h
5.Hard
VCss,avg​ = 15 mg/LD = ? mg · q8hCL = 0.03 L/kg/h95 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A 95 kg patient takes oral theophylline (F = 1) every 8 h. The clearance is 0.03 L/kg/h. What dose D in mg gives an average steady-state level of 15 mg/L?

CL = 0.03 L/kg/hτ = 8 hS = 1F = 195 kgCss,avg = 15 mg/L
D = mg
6.Hard
t (h)C (mg/L)Css​t = ?50%

Practice exercise (made-up values, not clinical guidance). A vancomycin infusion is started without a loading dose. The half-life in this patient is 10 h. How long t does it take to reach 50% of the steady-state level?

t½ = 10 h50% Css
t = h

Answer key

  1. 1. C = 4.375 mg/L
  2. 2. tss = 50 h
  3. 3. LD = 853.1 mg
  4. 4. R = 105 mg/h
  5. 5. D = 342 mg
  6. 6. t = 10 h

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