Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Vd = 0.25 L/kgC = 10 mg/LLD = ?73 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 73 kg needs a loading dose of gentamicin to reach a level of 10 mg/L straight away. The volume of distribution is 0.25 L/kg. Find the loading dose LD in mg.

73 kgVd = 0.25 L/kgC = 10 mg/L
LD = mg
2.Easy
t/t½C/Css (%)100%3f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives lidocaine as a constant IV infusion without a loading dose. The half-life is 2 h. What percentage f of the steady-state level has been reached after 6 h?

t½ = 2 ht = 6 h
f = %
3.Medium
VCss​ = 2 mg/LR = ? mg/minCL = 700 mL/min

Practice exercise (made-up values, not clinical guidance). A patient has a lidocaine clearance of 700 mL/min. What infusion rate R in mg/min keeps the steady-state level at 2 mg/L?

CL = 700 mL/minCss = 2 mg/L
R = mg/min
4.Medium
110100t (h)C (mg/L)1 h10 mg/L9 h1.6 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 10 mg/L at 1 h and 1.6 mg/L at 9 h. Assume first-order elimination. Find the half-life t½.

C1 = 10 mg/L (1 h)C2 = 1.6 mg/L (9 h)
t½ = h
5.Hard
t (h)C (mg/L)Css​t = ?90%

Practice exercise (made-up values, not clinical guidance). A vancomycin infusion is started without a loading dose. The half-life in this patient is 8 h. How long t does it take to reach 90% of the steady-state level?

t½ = 8 h90% Css
t = h
6.Hard
VCss,avg​ = 15 mg/LD = ? mg · q12hCL = 0.03 L/kg/h96 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 96 kg patient takes oral aminophylline (S = 0.8, F = 1) every 12 h. The theophylline clearance is 0.03 L/kg/h. What dose D in mg gives an average steady-state level of 15 mg/L?

CL = 0.03 L/kg/hτ = 12 hS = 0.8F = 196 kgCss,avg = 15 mg/L
D = mg

Answer key

  1. 1. LD = 182.5 mg
  2. 2. f = 87.5 %
  3. 3. R = 1.4 mg/min
  4. 4. t½ = 3.026 h
  5. 5. t = 26.58 h
  6. 6. D = 648 mg

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