Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Vd = 0.5 L/kgC = 10 mg/LLD = ?73 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 73 kg needs a loading dose of theophylline to reach a level of 10 mg/L straight away. The volume of distribution is 0.5 L/kg. Find the loading dose LD in mg.

73 kgVd = 0.5 L/kgC = 10 mg/L
LD = mg
2.Easy
Vd = 0.7 L/kgC = 30 mg/LLD = ?104 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 104 kg needs a loading dose of vancomycin to reach a level of 30 mg/L straight away. The volume of distribution is 0.7 L/kg. Find the loading dose LD in mg.

104 kgVd = 0.7 L/kgC = 30 mg/L
LD = mg
3.Medium
VCss​ = 4 mg/LR = ? mg/minCL = 500 mL/min

Practice exercise (made-up values, not clinical guidance). A patient has a lidocaine clearance of 500 mL/min. What infusion rate R in mg/min keeps the steady-state level at 4 mg/L?

CL = 500 mL/minCss = 4 mg/L
R = mg/min
4.Medium
110100t (h)C (mg/L)2 h10 mg/L6 h4 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 10 mg/L at 2 h and 4 mg/L at 6 h. Assume first-order elimination. Find the half-life t½.

C1 = 10 mg/L (2 h)C2 = 4 mg/L (6 h)
t½ = h
5.Hard
t (h)C (mg/L)Css​21 hC = ?

Practice exercise (made-up values, not clinical guidance). A theophylline infusion runs at 35 mg/h with no loading dose. The patient's clearance is 3.5 L/h and the half-life is 8 h. What is the level C after 21 h?

R = 35 mg/hCL = 3.5 L/ht½ = 8 ht = 21 h
C = mg/L
6.Hard
80 kg81 · manSCr 1.9 mg/dLfe​ = 0.9D = ? mg

Practice exercise (made-up values, not clinical guidance). An 81-year-old man weighs 80 kg and has a serum creatinine of 1.9 mg/dL (168 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual atenolol dose is 100 mg for a creatinine clearance of 100 mL/min, and a fraction fe = 0.9 of the drug is excreted unchanged by the kidneys. Using the Dettli dose fraction Q = 1 − fe·(1 − CrCl/normal CrCl), find the adjusted dose D. Round to the nearest whole number.

81 years80 kgmanSCr = 1.9 mg/dL100 mgfe = 0.9CrCl normal 100 mL/min
D = mg

Answer key

  1. 1. LD = 365 mg
  2. 2. LD = 2184 mg
  3. 3. R = 2 mg/min
  4. 4. t½ = 3.026 h
  5. 5. C = 8.379 mg/L
  6. 6. D = 41 mg

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