Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%2.5f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives aminophylline as a constant IV infusion without a loading dose. The half-life is 8 h. What percentage f of the steady-state level has been reached after 20 h?

t½ = 8 ht = 20 h
f = %
2.Easy
Vd = 0.5 L/kgC = 15 mg/LLD = ?59 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 59 kg needs a loading dose of theophylline to reach a level of 15 mg/L straight away. The volume of distribution is 0.5 L/kg. Find the loading dose LD in mg.

59 kgVd = 0.5 L/kgC = 15 mg/L
LD = mg
3.Medium
VCss​ = 25 mg/LR = ? mg/hCL = 60 mL/min

Practice exercise (made-up values, not clinical guidance). Vancomycin is given as a continuous infusion to a patient whose vancomycin clearance is 60 mL/min. What infusion rate R in mg/h gives a steady-state level of 25 mg/L?

CL = 60 mL/minCss = 25 mg/L
R = mg/h
4.Medium
110t (h)C (mg/L)C₀ = 8 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 230 mg of tobramycin. The level back-extrapolated to time zero is 8 mg/L and the half-life is 2.5 h. Find the clearance CL in L/h.

D = 230 mgC₀ = 8 mg/Lt½ = 2.5 h
CL = L/h
5.Hard
82 kg74 · manSCr 2.1 mg/dLCrCl → τ = ? h

Practice exercise (made-up values, not clinical guidance). A 74-year-old man weighs 82 kg and has a serum creatinine of 2.1 mg/dL (186 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual gentamicin regimen is 80 mg every 8 h for a creatinine clearance of 120 mL/min. Keeping the dose, the interval is lengthened in proportion to the fall in clearance. Find the new dosing interval τ. Round to one decimal place.

74 years82 kgmanSCr = 2.1 mg/dL80 mg q8hCrCl normal 120 mL/min
τ = h
6.Hard
Vd = 0.7 L/kg6 → 15 mg/LLD = ? mg55 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 55 kg patient has a phenytoin level of 6 mg/L; the target is 15 mg/L. The drug is given intravenously as phenytoin sodium (S = 0.92), and the volume of distribution is 0.7 L/kg. What extra loading dose LD raises the level to the target?

55 kgVd = 0.7 L/kgC = 6 → 15 mg/LS = 0.92
LD = mg

Answer key

  1. 1. f = 82.32 %
  2. 2. LD = 442.5 mg
  3. 3. R = 90 mg/h
  4. 4. CL = 7.971 L/h
  5. 5. τ = 26.8 h
  6. 6. LD = 376.6 mg

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