Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%1f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives lidocaine as a constant IV infusion without a loading dose. The half-life is 2 h. What percentage f of the steady-state level has been reached after 2 h?

t½ = 2 ht = 2 h
f = %
2.Easy
Vd = 0.5 L/kgC = 10 mg/LLD = ?63 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 63 kg needs a loading dose of theophylline to reach a level of 10 mg/L straight away. The volume of distribution is 0.5 L/kg. Find the loading dose LD in mg.

63 kgVd = 0.5 L/kgC = 10 mg/L
LD = mg
3.Medium
110100t (h)C (mg/L)C₀ = 10 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 200 mg of gentamicin. The level back-extrapolated to time zero is 10 mg/L and the half-life is 2.5 h. Find the clearance CL in L/h.

D = 200 mgC₀ = 10 mg/Lt½ = 2.5 h
CL = L/h
4.Medium
110100t (h)C (mg/L)1 h9 mg/L6 h3.3 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 9 mg/L at 1 h and 3.3 mg/L at 6 h. Assume first-order elimination. Find the half-life t½.

C1 = 9 mg/L (1 h)C2 = 3.3 mg/L (6 h)
t½ = h
5.Hard
t (h)C (mg/L)Css​23 hC = ?

Practice exercise (made-up values, not clinical guidance). A theophylline infusion runs at 42 mg/h with no loading dose. The patient's clearance is 3.5 L/h and the half-life is 8 h. What is the level C after 23 h?

R = 42 mg/hCL = 3.5 L/ht½ = 8 ht = 23 h
C = mg/L
6.Hard
Vd = 0.5 L/kg3.6 → 12 mg/LLD = ? mg50 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 50 kg patient has a theophylline level of 3.6 mg/L; the target is 12 mg/L. The drug is given intravenously as aminophylline (S = 0.8), and the volume of distribution is 0.5 L/kg. What extra loading dose LD raises the level to the target?

50 kgVd = 0.5 L/kgC = 3.6 → 12 mg/LS = 0.8
LD = mg

Answer key

  1. 1. f = 50 %
  2. 2. LD = 315 mg
  3. 3. CL = 5.545 L/h
  4. 4. t½ = 3.454 h
  5. 5. C = 10.36 mg/L
  6. 6. LD = 262.5 mg

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