Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Vd = 0.5 L/kgC = 10 mg/LLD = ?58 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 58 kg needs a loading dose of theophylline to reach a level of 10 mg/L straight away. The volume of distribution is 0.5 L/kg. Find the loading dose LD in mg.

58 kgVd = 0.5 L/kgC = 10 mg/L
LD = mg
2.Easy
110100t (h)CC₀t½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, gentamicin has an elimination half-life of 2.5 h. Find the elimination rate constant k in h⁻¹.

t½ = 2.5 h
k = h⁻¹
3.Medium
110t (h)C (mg/L)C₀ = 7 mg/Lt½ = 3.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 170 mg of gentamicin. The level back-extrapolated to time zero is 7 mg/L and the half-life is 3.5 h. Find the volume of distribution Vd.

D = 170 mgC₀ = 7 mg/Lt½ = 3.5 h
Vd = L
4.Medium
110100t (h)C (mg/L)C₀ = 12 mg/Lt½ = 3 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 290 mg of tobramycin. The level back-extrapolated to time zero is 12 mg/L and the half-life is 3 h. Find the volume of distribution Vd.

D = 290 mgC₀ = 12 mg/Lt½ = 3 h
Vd = L
5.Hard
Vd = 0.7 L/kg8 → 20 mg/LLD = ? mg97 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 97 kg patient has a phenytoin level of 8 mg/L; the target is 20 mg/L. The drug is given intravenously as phenytoin sodium (S = 0.92), and the volume of distribution is 0.7 L/kg. What extra loading dose LD raises the level to the target?

97 kgVd = 0.7 L/kgC = 8 → 20 mg/LS = 0.92
LD = mg
6.Hard
0.1110100t (h)C (mg/L)Cpeak​ = 10τ = ?Ctrough​ = 1

Practice exercise (made-up values, not clinical guidance). A patient's tobramycin half-life is 3 h. The target is a peak of 10 mg/L and a trough of 1 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 3 hCpeak = 10 mg/LCtrough = 1 mg/L
τ = h

Answer key

  1. 1. LD = 290 mg
  2. 2. k = 0.2773 h⁻¹
  3. 3. Vd = 24.29 L
  4. 4. Vd = 24.17 L
  5. 5. LD = 885.7 mg
  6. 6. τ = 10 h

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