Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
10100t (h)C (mg/L)40 mg/L11 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 40 mg/L. The half-life is 8 h, and the drug is eliminated by first-order kinetics. What is the level C 11 h later?

C₀ = 40 mg/Lt½ = 8 ht = 11 h
C = mg/L
2.Easy
t/t½C/Css (%)100%3.5f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives aminophylline as a constant IV infusion without a loading dose. The half-life is 6 h. What percentage f of the steady-state level has been reached after 21 h?

t½ = 6 ht = 21 h
f = %
3.Medium
VCss​ = 15 mg/LR = ? mg/hCL = 0.035 L/kg/h60 kg

Practice exercise (made-up values, not clinical guidance). A 60 kg patient receives a theophylline infusion. The clearance is 0.035 L/kg/h. What infusion rate R in mg/h gives a steady-state level of 15 mg/L?

60 kgCL = 0.035 L/kg/hCss = 15 mg/L
R = mg/h
4.Medium
VCss​ = 15 mg/LR = ? mg/h · S = 0.8CL = 0.035 L/kg/h66 kg

Practice exercise (made-up values, not clinical guidance). A 66 kg patient is to receive an aminophylline infusion (salt factor S = 0.8: 80% of aminophylline is theophylline). The theophylline clearance is 0.035 L/kg/h. What aminophylline infusion rate R in mg/h gives a steady-state theophylline level of 15 mg/L?

66 kgCL = 0.035 L/kg/hCss = 15 mg/LS = 0.8
R = mg/h
5.Hard
VCss,avg​ = 10 mg/LD = ? mg · q8hCL = 0.045 L/kg/h100 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A 100 kg patient takes oral theophylline (F = 1) every 8 h. The clearance is 0.045 L/kg/h. What dose D in mg gives an average steady-state level of 10 mg/L?

CL = 0.045 L/kg/hτ = 8 hS = 1F = 1100 kgCss,avg = 10 mg/L
D = mg
6.Hard
t (h)C (mg/L)Css​4 hC = ?

Practice exercise (made-up values, not clinical guidance). A theophylline infusion runs at 52.5 mg/h with no loading dose. The patient's clearance is 3.5 L/h and the half-life is 6 h. What is the level C after 4 h?

R = 52.5 mg/hCL = 3.5 L/ht½ = 6 ht = 4 h
C = mg/L

Answer key

  1. 1. C = 15.42 mg/L
  2. 2. f = 91.16 %
  3. 3. R = 31.5 mg/h
  4. 4. R = 43.31 mg/h
  5. 5. D = 360 mg
  6. 6. C = 5.551 mg/L

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