Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Vd = 0.5 L/kgC = 12 mg/LLD = ?104 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 104 kg needs a loading dose of theophylline to reach a level of 12 mg/L straight away. The volume of distribution is 0.5 L/kg. Find the loading dose LD in mg.

104 kgVd = 0.5 L/kgC = 12 mg/L
LD = mg
2.Easy
Vd = 0.7 L/kgC = 20 mg/LLD = ?101 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 101 kg needs a loading dose of vancomycin to reach a level of 20 mg/L straight away. The volume of distribution is 0.7 L/kg. Find the loading dose LD in mg.

101 kgVd = 0.7 L/kgC = 20 mg/L
LD = mg
3.Medium
Vd = 0.7 L/kgC = 20 mg/LLD = ? mg69 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 69 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 20 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.

69 kgVd = 0.7 L/kgC = 20 mg/LS = 0.92
LD = mg
4.Medium
Vd = 0.5 L/kgC = 15 mg/LLD = ? mg94 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 94 kg patient is to be loaded intravenously with aminophylline to reach a theophylline level of 15 mg/L. The volume of distribution is 0.5 L/kg and the salt factor is S = 0.8. Find the loading dose LD of aminophylline in mg.

94 kgVd = 0.5 L/kgC = 15 mg/LS = 0.8
LD = mg
5.Hard
VCss,avg​ = ?1250 mg · q12hCL = 6 L/hS = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A patient receives vancomycin IV every 12 h; the vancomycin clearance is 6 L/h. Each dose is 1250 mg of vancomycin. Find the average steady-state level Css,avg.

CL = 6 L/hτ = 12 hS = 1F = 1D = 1250 mg
Css,avg = mg/L
6.Hard
VCss,avg​ = ?450 mg · q12hCL = 0.035 L/kg/h51 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 51 kg patient takes oral aminophylline (S = 0.8, F = 1) every 12 h. The theophylline clearance is 0.035 L/kg/h. Each dose is 450 mg of aminophylline. Find the average steady-state level Css,avg.

CL = 0.035 L/kg/hτ = 12 hS = 0.8F = 151 kgD = 450 mg
Css,avg = mg/L

Answer key

  1. 1. LD = 624 mg
  2. 2. LD = 1414 mg
  3. 3. LD = 1050 mg
  4. 4. LD = 881.3 mg
  5. 5. Css,avg = 17.36 mg/L
  6. 6. Css,avg = 16.81 mg/L

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