Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)C (mg/L)10 mg/L4 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the tobramycin level is 10 mg/L. The half-life is 3 h, and the drug is eliminated by first-order kinetics. What is the level C 4 h later?

C₀ = 10 mg/Lt½ = 3 ht = 4 h
C = mg/L
2.Easy
10100t (h)C (mg/L)35 mg/L2 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 35 mg/L. The half-life is 9 h, and the drug is eliminated by first-order kinetics. What is the level C 2 h later?

C₀ = 35 mg/Lt½ = 9 ht = 2 h
C = mg/L
3.Medium
Vd = 7 L/kgC = 1 mcg/LLD = ? mcg50 kg · S = 1 · F = 0.7

Practice exercise (made-up values, not clinical guidance). A 50 kg patient is to be loaded with digoxin tablets to reach a level of 1 mcg/L. The volume of distribution is 7 L/kg and the tablets have a bioavailability F = 0.7. Find the total oral loading dose LD in mcg.

50 kgVd = 7 L/kgC = 1 mcg/LF = 0.7
LD = mcg
4.Medium
Vd = 7 L/kgC = 1 mcg/LLD = ? mcg99 kg · S = 1 · F = 0.7

Practice exercise (made-up values, not clinical guidance). A 99 kg patient is to be loaded with digoxin tablets to reach a level of 1 mcg/L. The volume of distribution is 7 L/kg and the tablets have a bioavailability F = 0.7. Find the total oral loading dose LD in mcg.

99 kgVd = 7 L/kgC = 1 mcg/LF = 0.7
LD = mcg
5.Hard
t (h)C (mg/L)Css​23 hC = ?

Practice exercise (made-up values, not clinical guidance). A theophylline infusion runs at 42 mg/h with no loading dose. The patient's clearance is 3.5 L/h and the half-life is 9 h. What is the level C after 23 h?

R = 42 mg/hCL = 3.5 L/ht½ = 9 ht = 23 h
C = mg/L
6.Hard
t (h)C (mg/L)Css​9 hC = ?

Practice exercise (made-up values, not clinical guidance). A vancomycin infusion runs at 125 mg/h with no loading dose. The patient's clearance is 5 L/h and the half-life is 8 h. What is the level C after 9 h?

R = 125 mg/hCL = 5 L/ht½ = 8 ht = 9 h
C = mg/L

Answer key

  1. 1. C = 3.969 mg/L
  2. 2. C = 30 mg/L
  3. 3. LD = 500 mcg
  4. 4. LD = 990 mcg
  5. 5. C = 9.959 mg/L
  6. 6. C = 13.54 mg/L

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