Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Vd = 0.7 L/kgC = 20 mg/LLD = ?93 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 93 kg needs a loading dose of vancomycin to reach a level of 20 mg/L straight away. The volume of distribution is 0.7 L/kg. Find the loading dose LD in mg.

93 kgVd = 0.7 L/kgC = 20 mg/L
LD = mg
2.Easy
110100t (h)CC₀t½ = 9 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, vancomycin has an elimination half-life of 9 h. Find the elimination rate constant k in h⁻¹.

t½ = 9 h
k = h⁻¹
3.Medium
110t (h)C (mg/L)1 h8 mg/L5 h3.2 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 8 mg/L at 1 h and 3.2 mg/L at 5 h. Assume first-order elimination. Find the half-life t½.

C1 = 8 mg/L (1 h)C2 = 3.2 mg/L (5 h)
t½ = h
4.Medium
110t (h)C (mg/L)C₀ = 7 mg/Lt½ = 3 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 210 mg of tobramycin. The level back-extrapolated to time zero is 7 mg/L and the half-life is 3 h. Find the clearance CL in L/h.

D = 210 mgC₀ = 7 mg/Lt½ = 3 h
CL = L/h
5.Hard
Vd = 0.7 L/kg8 → 20 mg/LLD = ? mg66 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 66 kg patient has a phenytoin level of 8 mg/L; the target is 20 mg/L. The drug is given intravenously as phenytoin sodium (S = 0.92), and the volume of distribution is 0.7 L/kg. What extra loading dose LD raises the level to the target?

66 kgVd = 0.7 L/kgC = 8 → 20 mg/LS = 0.92
LD = mg
6.Hard
t (h)C (mg/L)Css​10 hC = ?

Practice exercise (made-up values, not clinical guidance). A vancomycin infusion runs at 100 mg/h with no loading dose. The patient's clearance is 5 L/h and the half-life is 6 h. What is the level C after 10 h?

R = 100 mg/hCL = 5 L/ht½ = 6 ht = 10 h
C = mg/L

Answer key

  1. 1. LD = 1302 mg
  2. 2. k = 0.07702 h⁻¹
  3. 3. t½ = 3.026 h
  4. 4. CL = 6.931 L/h
  5. 5. LD = 602.6 mg
  6. 6. C = 13.7 mg/L

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