Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%1f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives aminophylline as a constant IV infusion without a loading dose. The half-life is 8 h. What percentage f of the steady-state level has been reached after 8 h?

t½ = 8 ht = 8 h
f = %
2.Easy
110100t (h)CC₀t½ = ?C₀/2

Practice exercise (made-up values, not clinical guidance). The elimination rate constant of tobramycin in a patient is 0.347 h⁻¹. Find the half-life t½.

k = 0.347 h⁻¹
t½ = h
3.Medium
Vd = 0.7 L/kgC = 15 mg/LLD = ? mg52 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 52 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 15 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.

52 kgVd = 0.7 L/kgC = 15 mg/LS = 0.92
LD = mg
4.Medium
110t (h)C (mg/L)C₀ = 7 mg/Lt½ = 3 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 140 mg of tobramycin. The level back-extrapolated to time zero is 7 mg/L and the half-life is 3 h. Find the clearance CL in L/h.

D = 140 mgC₀ = 7 mg/Lt½ = 3 h
CL = L/h
5.Hard
t (h)C (mg/L)Css​t = ?95%

Practice exercise (made-up values, not clinical guidance). A theophylline infusion is started without a loading dose. The half-life in this patient is 8 h. How long t does it take to reach 95% of the steady-state level?

t½ = 8 h95% Css
t = h
6.Hard
0.1110t (h)C (mg/L)Cpeak​ = 7τ = ?Ctrough​ = 1

Practice exercise (made-up values, not clinical guidance). A patient's gentamicin half-life is 3.5 h. The target is a peak of 7 mg/L and a trough of 1 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 3.5 hCpeak = 7 mg/LCtrough = 1 mg/L
τ = h

Answer key

  1. 1. f = 50 %
  2. 2. t½ = 1.998 h
  3. 3. LD = 593.5 mg
  4. 4. CL = 4.621 L/h
  5. 5. t = 34.58 h
  6. 6. τ = 9.8 h

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