Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110t (h)C (mg/L)6 mg/L4 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the gentamicin level is 6 mg/L. The half-life is 3 h, and the drug is eliminated by first-order kinetics. What is the level C 4 h later?

C₀ = 6 mg/Lt½ = 3 ht = 4 h
C = mg/L
2.Easy
t/t½C/Css (%)100%597%

Practice exercise (made-up values, not clinical guidance). A patient starts regular doses of gentamicin, which has a half-life of 3 h. Using the rule that steady state is reached after about five half-lives, after how many hours tss is steady state reached?

t½ = 3 h
tss = h
3.Medium
VCss​ = 25 mg/LR = ? mg/hCL = 3 L/h

Practice exercise (made-up values, not clinical guidance). Vancomycin is given as a continuous infusion to a patient whose vancomycin clearance is 3 L/h. What infusion rate R in mg/h gives a steady-state level of 25 mg/L?

CL = 3 L/hCss = 25 mg/L
R = mg/h
4.Medium
110100t (h)C (mg/L)2 h25 mg/L12 h9.3 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of vancomycin, the level is 25 mg/L at 2 h and 9.3 mg/L at 12 h. Assume first-order elimination. Find the half-life t½.

C1 = 25 mg/L (2 h)C2 = 9.3 mg/L (12 h)
t½ = h
5.Hard
76 kg74 · womanSCr 1.2 mg/dLCrCl → D = ? mg

Practice exercise (made-up values, not clinical guidance). A 74-year-old woman weighs 76 kg and has a serum creatinine of 1.2 mg/dL (106 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual gentamicin dose is 120 mg every 8 h for a creatinine clearance of 120 mL/min. Keeping the interval, the dose is reduced in proportion to the creatinine clearance. Find the adjusted dose D. Round to the nearest whole number.

74 years76 kgwomanSCr = 1.2 mg/dL120 mg q8hCrCl normal 120 mL/min
D = mg
6.Hard
VCss,avg​ = 25 mg/LD = ? mg · q12hCL = 5 L/hS = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A patient receives vancomycin IV every 12 h; the vancomycin clearance is 5 L/h. What dose D in mg gives an average steady-state level of 25 mg/L?

CL = 5 L/hτ = 12 hS = 1F = 1Css,avg = 25 mg/L
D = mg

Answer key

  1. 1. C = 2.381 mg/L
  2. 2. tss = 15 h
  3. 3. R = 75 mg/h
  4. 4. t½ = 7.01 h
  5. 5. D = 49 mg
  6. 6. D = 1500 mg

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