Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%597%

Practice exercise (made-up values, not clinical guidance). A patient starts regular doses of theophylline, which has a half-life of 6 h. Using the rule that steady state is reached after about five half-lives, after how many hours tss is steady state reached?

t½ = 6 h
tss = h
2.Easy
110100t (h)C (mg/L)30 mg/L35 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 30 mg/L. The half-life is 10 h, and the drug is eliminated by first-order kinetics. What is the level C 35 h later?

C₀ = 30 mg/Lt½ = 10 ht = 35 h
C = mg/L
3.Medium
VCss​ = 15 mg/LR = ? mg/hCL = 0.05 L/kg/h61 kg

Practice exercise (made-up values, not clinical guidance). A 61 kg patient receives a theophylline infusion. The clearance is 0.05 L/kg/h. What infusion rate R in mg/h gives a steady-state level of 15 mg/L?

61 kgCL = 0.05 L/kg/hCss = 15 mg/L
R = mg/h
4.Medium
110t (h)C (mg/L)C₀ = 8 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 110 mg of gentamicin. The level back-extrapolated to time zero is 8 mg/L and the half-life is 2.5 h. Find the clearance CL in L/h.

D = 110 mgC₀ = 8 mg/Lt½ = 2.5 h
CL = L/h
5.Hard
76 kg45 · manSCr 1.7 mg/dLCrCl → D = ? mg

Practice exercise (made-up values, not clinical guidance). A 45-year-old man weighs 76 kg and has a serum creatinine of 1.7 mg/dL (150 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual gentamicin dose is 120 mg every 8 h for a creatinine clearance of 100 mL/min. Keeping the interval, the dose is reduced in proportion to the creatinine clearance. Find the adjusted dose D. Round to the nearest whole number.

45 years76 kgmanSCr = 1.7 mg/dL120 mg q8hCrCl normal 100 mL/min
D = mg
6.Hard
Vd = 0.5 L/kg5 → 10 mg/LLD = ? mg64 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 64 kg patient has a theophylline level of 5 mg/L; the target is 10 mg/L. The drug is given intravenously as aminophylline (S = 0.8), and the volume of distribution is 0.5 L/kg. What extra loading dose LD raises the level to the target?

64 kgVd = 0.5 L/kgC = 5 → 10 mg/LS = 0.8
LD = mg

Answer key

  1. 1. tss = 30 h
  2. 2. C = 2.652 mg/L
  3. 3. R = 45.75 mg/h
  4. 4. CL = 3.812 L/h
  5. 5. D = 71 mg
  6. 6. LD = 200 mg

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