Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%1.5f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives aminophylline as a constant IV infusion without a loading dose. The half-life is 9 h. What percentage f of the steady-state level has been reached after 13.5 h?

t½ = 9 ht = 13.5 h
f = %
2.Easy
Vd = 0.25 L/kgC = 10 mg/LLD = ?91 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 91 kg needs a loading dose of gentamicin to reach a level of 10 mg/L straight away. The volume of distribution is 0.25 L/kg. Find the loading dose LD in mg.

91 kgVd = 0.25 L/kgC = 10 mg/L
LD = mg
3.Medium
110t (h)C (mg/L)C₀ = 6 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 160 mg of gentamicin. The level back-extrapolated to time zero is 6 mg/L and the half-life is 2.5 h. Find the volume of distribution Vd.

D = 160 mgC₀ = 6 mg/Lt½ = 2.5 h
Vd = L
4.Medium
110t (h)C (mg/L)C₀ = 7 mg/Lt½ = 2 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 130 mg of tobramycin. The level back-extrapolated to time zero is 7 mg/L and the half-life is 2 h. Find the clearance CL in L/h.

D = 130 mgC₀ = 7 mg/Lt½ = 2 h
CL = L/h
5.Hard
t (h)C (mg/L)Css​7 hC = ?

Practice exercise (made-up values, not clinical guidance). A vancomycin infusion runs at 75 mg/h with no loading dose. The patient's clearance is 3 L/h and the half-life is 6 h. What is the level C after 7 h?

R = 75 mg/hCL = 3 L/ht½ = 6 ht = 7 h
C = mg/L
6.Hard
0.1110t (h)C (mg/L)Cpeak​ = 6τ = ?Ctrough​ = 0.5

Practice exercise (made-up values, not clinical guidance). A patient's gentamicin half-life is 4 h. The target is a peak of 6 mg/L and a trough of 0.5 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 4 hCpeak = 6 mg/LCtrough = 0.5 mg/L
τ = h

Answer key

  1. 1. f = 64.64 %
  2. 2. LD = 227.5 mg
  3. 3. Vd = 26.67 L
  4. 4. CL = 6.436 L/h
  5. 5. C = 13.86 mg/L
  6. 6. τ = 14.3 h

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