Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)C (mg/L)30 mg/L33 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 30 mg/L. The half-life is 10 h, and the drug is eliminated by first-order kinetics. What is the level C 33 h later?

C₀ = 30 mg/Lt½ = 10 ht = 33 h
C = mg/L
2.Easy
110100t (h)C (mg/L)10 mg/L2.5 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the tobramycin level is 10 mg/L. The half-life is 2.5 h, and the drug is eliminated by first-order kinetics. What is the level C 2.5 h later?

C₀ = 10 mg/Lt½ = 2.5 ht = 2.5 h
C = mg/L
3.Medium
VCss​ = 20 mg/LR = ? mg/hCL = 80 mL/min

Practice exercise (made-up values, not clinical guidance). Vancomycin is given as a continuous infusion to a patient whose vancomycin clearance is 80 mL/min. What infusion rate R in mg/h gives a steady-state level of 20 mg/L?

CL = 80 mL/minCss = 20 mg/L
R = mg/h
4.Medium
Vd = 0.5 L/kgC = 12 mg/LLD = ? mg56 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 56 kg patient is to be loaded intravenously with aminophylline to reach a theophylline level of 12 mg/L. The volume of distribution is 0.5 L/kg and the salt factor is S = 0.8. Find the loading dose LD of aminophylline in mg.

56 kgVd = 0.5 L/kgC = 12 mg/LS = 0.8
LD = mg
5.Hard
Vd = 0.5 L/kg5 → 10 mg/LLD = ? mg77 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 77 kg patient has a theophylline level of 5 mg/L; the target is 10 mg/L. The drug is given intravenously as aminophylline (S = 0.8), and the volume of distribution is 0.5 L/kg. What extra loading dose LD raises the level to the target?

77 kgVd = 0.5 L/kgC = 5 → 10 mg/LS = 0.8
LD = mg
6.Hard
VCss,avg​ = ?450 mg · q8hCL = 0.045 L/kg/h88 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). An 88 kg patient takes oral theophylline (F = 1) every 8 h. The clearance is 0.045 L/kg/h. Each dose is 450 mg of theophylline. Find the average steady-state level Css,avg.

CL = 0.045 L/kg/hτ = 8 hS = 1F = 188 kgD = 450 mg
Css,avg = mg/L

Answer key

  1. 1. C = 3.046 mg/L
  2. 2. C = 5 mg/L
  3. 3. R = 96 mg/h
  4. 4. LD = 420 mg
  5. 5. LD = 240.6 mg
  6. 6. Css,avg = 14.2 mg/L

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