Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)CC₀t½ = ?C₀/2

Practice exercise (made-up values, not clinical guidance). The elimination rate constant of digoxin in a patient is 0.0144 h⁻¹. Find the half-life t½.

k = 0.0144 h⁻¹
t½ = h
2.Easy
t/t½C/Css (%)100%597%

Practice exercise (made-up values, not clinical guidance). A patient starts regular doses of phenobarbital, which has a half-life of 96 h. Using the rule that steady state is reached after about five half-lives, after how many hours tss is steady state reached?

t½ = 96 h
tss = h
3.Medium
110t (h)C (mg/L)1 h8 mg/L5 h3.2 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 8 mg/L at 1 h and 3.2 mg/L at 5 h. Assume first-order elimination. Find the half-life t½.

C1 = 8 mg/L (1 h)C2 = 3.2 mg/L (5 h)
t½ = h
4.Medium
110t (h)C (mg/L)C₀ = 7 mg/Lt½ = 3 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 180 mg of tobramycin. The level back-extrapolated to time zero is 7 mg/L and the half-life is 3 h. Find the volume of distribution Vd.

D = 180 mgC₀ = 7 mg/Lt½ = 3 h
Vd = L
5.Hard
VCss,avg​ = ?500 mg · q12hCL = 0.035 L/kg/h70 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A 70 kg patient takes oral theophylline (F = 1) every 12 h. The clearance is 0.035 L/kg/h. Each dose is 500 mg of theophylline. Find the average steady-state level Css,avg.

CL = 0.035 L/kg/hτ = 12 hS = 1F = 170 kgD = 500 mg
Css,avg = mg/L
6.Hard
61 kg41 · womanSCr 2 mg/dLCrCl → D = ? mg

Practice exercise (made-up values, not clinical guidance). A 41-year-old woman weighs 61 kg and has a serum creatinine of 2 mg/dL (177 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual vancomycin dose is 1000 mg every 12 h for a creatinine clearance of 120 mL/min. Keeping the interval, the dose is reduced in proportion to the creatinine clearance. Find the adjusted dose D. Round to the nearest whole number.

41 years61 kgwomanSCr = 2 mg/dL1000 mg q12hCrCl normal 120 mL/min
D = mg

Answer key

  1. 1. t½ = 48.14 h
  2. 2. tss = 480 h
  3. 3. t½ = 3.026 h
  4. 4. Vd = 25.71 L
  5. 5. Css,avg = 17.01 mg/L
  6. 6. D = 297 mg

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