Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
t/t½C/Css (%)100%1f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives lidocaine as a constant IV infusion without a loading dose. The half-life is 1.5 h. What percentage f of the steady-state level has been reached after 1.5 h?

t½ = 1.5 ht = 1.5 h
f = %
2.Easy
Vd = 0.7 L/kgC = 30 mg/LLD = ?90 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 90 kg needs a loading dose of vancomycin to reach a level of 30 mg/L straight away. The volume of distribution is 0.7 L/kg. Find the loading dose LD in mg.

90 kgVd = 0.7 L/kgC = 30 mg/L
LD = mg
3.Medium
Vd = 0.7 L/kgC = 20 mg/LLD = ? mg83 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). An 83 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 20 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.

83 kgVd = 0.7 L/kgC = 20 mg/LS = 0.92
LD = mg
4.Medium
110100t (h)C (mg/L)C₀ = 10 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 180 mg of tobramycin. The level back-extrapolated to time zero is 10 mg/L and the half-life is 2.5 h. Find the clearance CL in L/h.

D = 180 mgC₀ = 10 mg/Lt½ = 2.5 h
CL = L/h
5.Hard
0.1110t (h)C (mg/L)Cpeak​ = 6τ = ?Ctrough​ = 0.5

Practice exercise (made-up values, not clinical guidance). A patient's gentamicin half-life is 4 h. The target is a peak of 6 mg/L and a trough of 0.5 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 4 hCpeak = 6 mg/LCtrough = 0.5 mg/L
τ = h
6.Hard
91 kg63 · womanSCr 1.3 mg/dLCrCl → τ = ? h

Practice exercise (made-up values, not clinical guidance). A 63-year-old woman weighs 91 kg and has a serum creatinine of 1.3 mg/dL (115 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual vancomycin regimen is 1000 mg every 12 h for a creatinine clearance of 100 mL/min. Keeping the dose, the interval is lengthened in proportion to the fall in clearance. Find the new dosing interval τ. Round to one decimal place.

63 years91 kgwomanSCr = 1.3 mg/dL1000 mg q12hCrCl normal 100 mL/min
τ = h

Answer key

  1. 1. f = 50 %
  2. 2. LD = 1890 mg
  3. 3. LD = 1263 mg
  4. 4. CL = 4.991 L/h
  5. 5. τ = 14.3 h
  6. 6. τ = 18.9 h

Full step-by-step solutions: practise this topic on examproblems.com.