Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
10100t (h)C (mg/L)40 mg/L1 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 40 mg/L. The half-life is 6 h, and the drug is eliminated by first-order kinetics. What is the level C 1 h later?

C₀ = 40 mg/Lt½ = 6 ht = 1 h
C = mg/L
2.Easy
Vd = 0.25 L/kgC = 8 mg/LLD = ?96 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 96 kg needs a loading dose of gentamicin to reach a level of 8 mg/L straight away. The volume of distribution is 0.25 L/kg. Find the loading dose LD in mg.

96 kgVd = 0.25 L/kgC = 8 mg/L
LD = mg
3.Medium
110t (h)C (mg/L)2 h8 mg/L7 h3 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 8 mg/L at 2 h and 3 mg/L at 7 h. Assume first-order elimination. Find the half-life t½.

C1 = 8 mg/L (2 h)C2 = 3 mg/L (7 h)
t½ = h
4.Medium
Vd = 0.7 L/kgC = 20 mg/LLD = ? mg79 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 79 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 20 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.

79 kgVd = 0.7 L/kgC = 20 mg/LS = 0.92
LD = mg
5.Hard
VCss,avg​ = ?300 mg · q8hCL = 0.03 L/kg/h80 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). An 80 kg patient takes oral theophylline (F = 1) every 8 h. The clearance is 0.03 L/kg/h. Each dose is 300 mg of theophylline. Find the average steady-state level Css,avg.

CL = 0.03 L/kg/hτ = 8 hS = 1F = 180 kgD = 300 mg
Css,avg = mg/L
6.Hard
t (h)C (mg/L)Css​t = ?95%

Practice exercise (made-up values, not clinical guidance). A vancomycin infusion is started without a loading dose. The half-life in this patient is 10 h. How long t does it take to reach 95% of the steady-state level?

t½ = 10 h95% Css
t = h

Answer key

  1. 1. C = 35.64 mg/L
  2. 2. LD = 192 mg
  3. 3. t½ = 3.533 h
  4. 4. LD = 1202 mg
  5. 5. Css,avg = 15.63 mg/L
  6. 6. t = 43.22 h

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