Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Vd = 0.25 L/kgC = 10 mg/LLD = ?97 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 97 kg needs a loading dose of gentamicin to reach a level of 10 mg/L straight away. The volume of distribution is 0.25 L/kg. Find the loading dose LD in mg.

97 kgVd = 0.25 L/kgC = 10 mg/L
LD = mg
2.Easy
110100t (h)CC₀t½ = 36 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, digoxin has an elimination half-life of 36 h. Find the elimination rate constant k in h⁻¹.

t½ = 36 h
k = h⁻¹
3.Medium
110t (h)C (mg/L)1 h6 mg/L6 h1.9 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 6 mg/L at 1 h and 1.9 mg/L at 6 h. Assume first-order elimination. Find the half-life t½.

C1 = 6 mg/L (1 h)C2 = 1.9 mg/L (6 h)
t½ = h
4.Medium
110100t (h)C (mg/L)C₀ = 12 mg/Lt½ = 3 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 310 mg of gentamicin. The level back-extrapolated to time zero is 12 mg/L and the half-life is 3 h. Find the clearance CL in L/h.

D = 310 mgC₀ = 12 mg/Lt½ = 3 h
CL = L/h
5.Hard
51 kg60 · manSCr 1.3 mg/dLfe​ = 0.66D = ? mg

Practice exercise (made-up values, not clinical guidance). A 60-year-old man weighs 51 kg and has a serum creatinine of 1.3 mg/dL (115 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual levetiracetam dose is 1000 mg for a creatinine clearance of 100 mL/min, and a fraction fe = 0.66 of the drug is excreted unchanged by the kidneys. Using the Dettli dose fraction Q = 1 − fe·(1 − CrCl/normal CrCl), find the adjusted dose D. Round to the nearest whole number.

60 years51 kgmanSCr = 1.3 mg/dL1000 mgfe = 0.66CrCl normal 100 mL/min
D = mg
6.Hard
t (h)C (mg/L)Css​t = ?95%

Practice exercise (made-up values, not clinical guidance). A theophylline infusion is started without a loading dose. The half-life in this patient is 9 h. How long t does it take to reach 95% of the steady-state level?

t½ = 9 h95% Css
t = h

Answer key

  1. 1. LD = 242.5 mg
  2. 2. k = 0.01925 h⁻¹
  3. 3. t½ = 3.014 h
  4. 4. CL = 5.969 L/h
  5. 5. D = 628 mg
  6. 6. t = 38.9 h

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