Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

New worksheetPractise online with hints

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
110100t (h)CC₀t½ = 1.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, lidocaine has an elimination half-life of 1.5 h. Find the elimination rate constant k in h⁻¹.

t½ = 1.5 h
k = h⁻¹
2.Easy
0.1110t (h)C (mg/L)6 mg/L7.5 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the gentamicin level is 6 mg/L. The half-life is 2.5 h, and the drug is eliminated by first-order kinetics. What is the level C 7.5 h later?

C₀ = 6 mg/Lt½ = 2.5 ht = 7.5 h
C = mg/L
3.Medium
0.1110t (h)C (mg/L)2 h6 mg/L8 h0.8 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 6 mg/L at 2 h and 0.8 mg/L at 8 h. Assume first-order elimination. Find the half-life t½.

C1 = 6 mg/L (2 h)C2 = 0.8 mg/L (8 h)
t½ = h
4.Medium
10100t (h)C (mg/L)1 h35 mg/L9 h13.9 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of vancomycin, the level is 35 mg/L at 1 h and 13.9 mg/L at 9 h. Assume first-order elimination. Find the half-life t½.

C1 = 35 mg/L (1 h)C2 = 13.9 mg/L (9 h)
t½ = h
5.Hard
VCss,avg​ = 15 mg/LD = ? mg · q8hCL = 0.045 L/kg/h50 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 50 kg patient takes oral aminophylline (S = 0.8, F = 1) every 8 h. The theophylline clearance is 0.045 L/kg/h. What dose D in mg gives an average steady-state level of 15 mg/L?

CL = 0.045 L/kg/hτ = 8 hS = 0.8F = 150 kgCss,avg = 15 mg/L
D = mg
6.Hard
t (h)C (mg/L)Css​11 hC = ?

Practice exercise (made-up values, not clinical guidance). A vancomycin infusion runs at 100 mg/h with no loading dose. The patient's clearance is 4 L/h and the half-life is 10 h. What is the level C after 11 h?

R = 100 mg/hCL = 4 L/ht½ = 10 ht = 11 h
C = mg/L

Answer key

  1. 1. k = 0.4621 h⁻¹
  2. 2. C = 0.75 mg/L
  3. 3. t½ = 2.064 h
  4. 4. t½ = 6.005 h
  5. 5. D = 337.5 mg
  6. 6. C = 13.34 mg/L

Full step-by-step solutions: practise this topic on examproblems.com.