Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)CC₀t½ = ?C₀/2

Practice exercise (made-up values, not clinical guidance). The elimination rate constant of vancomycin in a patient is 0.0866 h⁻¹. Find the half-life t½.

k = 0.0866 h⁻¹
t½ = h
2.Easy
t/t½C/Css (%)100%1f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives aminophylline as a constant IV infusion without a loading dose. The half-life is 8 h. What percentage f of the steady-state level has been reached after 8 h?

t½ = 8 ht = 8 h
f = %
3.Medium
VCss​ = 25 mg/LR = ? mg/hCL = 5 L/h

Practice exercise (made-up values, not clinical guidance). Vancomycin is given as a continuous infusion to a patient whose vancomycin clearance is 5 L/h. What infusion rate R in mg/h gives a steady-state level of 25 mg/L?

CL = 5 L/hCss = 25 mg/L
R = mg/h
4.Medium
110t (h)C (mg/L)C₀ = 8 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 190 mg of gentamicin. The level back-extrapolated to time zero is 8 mg/L and the half-life is 2.5 h. Find the clearance CL in L/h.

D = 190 mgC₀ = 8 mg/Lt½ = 2.5 h
CL = L/h
5.Hard
Vd = 0.5 L/kg6 → 15 mg/LLD = ? mg82 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). An 82 kg patient has a theophylline level of 6 mg/L; the target is 15 mg/L. The drug is given intravenously as aminophylline (S = 0.8), and the volume of distribution is 0.5 L/kg. What extra loading dose LD raises the level to the target?

82 kgVd = 0.5 L/kgC = 6 → 15 mg/LS = 0.8
LD = mg
6.Hard
VCss,avg​ = ?500 mg · q12hCL = 0.05 L/kg/h67 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A 67 kg patient takes oral theophylline (F = 1) every 12 h. The clearance is 0.05 L/kg/h. Each dose is 500 mg of theophylline. Find the average steady-state level Css,avg.

CL = 0.05 L/kg/hτ = 12 hS = 1F = 167 kgD = 500 mg
Css,avg = mg/L

Answer key

  1. 1. t½ = 8.004 h
  2. 2. f = 50 %
  3. 3. R = 125 mg/h
  4. 4. CL = 6.585 L/h
  5. 5. LD = 461.3 mg
  6. 6. Css,avg = 12.44 mg/L

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