Column buckling worksheet with answers

Free printable Column buckling worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
PL = 1 md = 20 mmcross-section

A column of length L made of aluminium is pinned at both ends. Using Euler’s formula, find its critical buckling load Pcr.

L = 1 mE = 70 GPa (aluminium)d = 20 mm
Pcr = kN
2.Easy
PL = 5 md = 60 mmcross-section

A column of length L made of steel is pinned at both ends. Using Euler’s formula, find its critical buckling load Pcr.

L = 5 mE = 200 GPa (steel)d = 60 mm
Pcr = kN
3.Medium
PL = 2 m20 × 60 mmcross-section

A column of length L made of aluminium is fixed at both ends. Using Euler’s formula, find its critical buckling load Pcr.

L = 2 mE = 70 GPa (aluminium)b × h = 20 × 60 mm
Pcr = kN
4.Medium
PL = 6 md = 60 mmcross-section

A column of length L made of steel is fixed at both ends. Using Euler’s formula, find its critical buckling load Pcr.

L = 6 mE = 200 GPa (steel)d = 60 mm
Pcr = kN
5.Hard
P = 70 kNL = 1.5 md = ?cross-section

A solid round column of length L made of steel is fixed at the base and pinned at the top. It must carry 70 kN with a factor of safety of 2 against buckling. Find the smallest diameter d.

P = 70 kNn = 2L = 1.5 mE = 200 GPa (steel)
d = mm
6.Hard
PL = 1.5 md = 60 mmcross-section

A column of length L made of steel is fixed at the base and free at the top. Find its slenderness and the critical buckling stress σcr from Euler’s formula.

L = 1.5 mE = 200 GPa (steel)d = 60 mm
σcr = MPa

Answer key

  1. 1. Pcr = 5.426 kN
  2. 2. Pcr = 50.23 kN
  3. 3. Pcr = 27.63 kN
  4. 4. Pcr = 139.5 kN
  5. 5. d = 35.53 mm
  6. 6. σcr = 49.35 MPa

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