A column of length L made of steel is pinned at both ends. Using Euler’s formula, find its critical buckling load Pcr.
Column buckling worksheet with answers
1.Easy
L = 4 mE = 200 GPa (steel)d = 60 mm
Pcr = kN
2.Easy
A column of length L made of aluminium is pinned at both ends. Using Euler’s formula, find its critical buckling load Pcr.
L = 3 mE = 70 GPa (aluminium)d = 50 mm
Pcr = kN
3.Medium
A column of length L made of aluminium is fixed at both ends. Using Euler’s formula, find its critical buckling load Pcr.
L = 3 mE = 70 GPa (aluminium)d = 20 mm
Pcr = kN
4.Medium
A column of length L made of steel is fixed at the base and pinned at the top. Using Euler’s formula, find its critical buckling load Pcr.
L = 6 mE = 200 GPa (steel)d = 80 mm
Pcr = kN
5.Hard
A column of length L made of steel is pinned at both ends. Find its slenderness and the critical buckling stress σcr from Euler’s formula.
L = 2.5 mE = 200 GPa (steel)d = 40 mm
σcr = MPa
6.Hard
A column of length L made of steel is fixed at both ends. Find its slenderness and the critical buckling stress σcr from Euler’s formula.
L = 4 mE = 200 GPa (steel)d = 30 mm
σcr = MPa
Answer key
- 1. Pcr = 78.48 kN
- 2. Pcr = 23.55 kN
- 3. Pcr = 2.412 kN
- 4. Pcr = 225 kN
- 5. σcr = 31.58 MPa
- 6. σcr = 27.76 MPa
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