Column buckling worksheet with answers

Free printable Column buckling worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
PL = 2 md = 80 mmcross-section

A column of length L made of aluminium is pinned at both ends. Using Euler’s formula, find its critical buckling load Pcr.

L = 2 mE = 70 GPa (aluminium)d = 80 mm
Pcr = kN
2.Easy
PL = 4 md = 50 mmcross-section

A column of length L made of steel is pinned at both ends. Using Euler’s formula, find its critical buckling load Pcr.

L = 4 mE = 200 GPa (steel)d = 50 mm
Pcr = kN
3.Medium
PL = 2 md = 25 mmcross-section

A column of length L made of aluminium is fixed at the base and pinned at the top. Using Euler’s formula, find its critical buckling load Pcr.

L = 2 mE = 70 GPa (aluminium)d = 25 mm
Pcr = kN
4.Medium
PL = 2 m25 × 100 mmcross-section

A column of length L made of steel is fixed at the base and free at the top. Using Euler’s formula, find its critical buckling load Pcr.

L = 2 mE = 200 GPa (steel)b × h = 25 × 100 mm
Pcr = kN
5.Hard
PL = 2 md = 25 mmcross-section

A column of length L made of steel is fixed at the base and free at the top. Find its slenderness and the critical buckling stress σcr from Euler’s formula.

L = 2 mE = 200 GPa (steel)d = 25 mm
σcr = MPa
6.Hard
PL = 2 md = 50 mmcross-section

A column of length L made of aluminium is fixed at the base and pinned at the top. Find its slenderness and the critical buckling stress σcr from Euler’s formula.

L = 2 mE = 70 GPa (aluminium)d = 50 mm
σcr = MPa

Answer key

  1. 1. Pcr = 347.3 kN
  2. 2. Pcr = 37.85 kN
  3. 3. Pcr = 6.759 kN
  4. 4. Pcr = 16.06 kN
  5. 5. σcr = 4.819 MPa
  6. 6. σcr = 55.08 MPa

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