For z₁ = −1 + j4 and z₂ = 2 − j4, find the imaginary part of the product z₁·z₂.
Complex numbers worksheet with answers
1.Easy
z₁ = −1 + j4z₂ = 2 − j4
Im(z₁z₂) =
2.Easy
For z₁ = 7 − j2 and z₂ = 6 − j3, find the real part of w = −z₁ − 2z₂.
z₁ = 7 − j2z₂ = 6 − j3
Re(w) =
3.Medium
Given z₁ = 5∠150° and z₂ = 1.5∠65°, find the argument θ of w = z₁/z₂ in degrees, between −180° and 180°.
z₁ = 5∠150°z₂ = 1.5∠65°
θ = °
4.Medium
The diagram shows z = 3 − j4. With w = 2∠−90°, click the point that represents z·w.
z = 3 − j4w = 2∠−90°
- 1A (−4 − j3)
- 2B (−8 − j6)
- 3C (6 − j8)
- 4D (8 + j6)
5.Hard
Exactly one of the points A–D is a root of z³ = 8∠−90°. Click it.
w = 8∠−90°n = 3
- 1A (3.6∠30°)
- 2B (2∠−30°)
- 3C (2∠150°)
- 4D (2∠−90°)
6.Hard
The roots of zⁿ = w with n = 6 and w = 729∠180° are zk = R1/n∠((φ + 360°·k)/n), k = 0, 1, …, 5. Find the argument of z₄ in degrees, between −180° and 180°.
w = 729∠180°n = 6k = 4
θ₄ = °
Answer key
- 1. Im(z₁z₂) = 12
- 2. Re(w) = −19
- 3. θ = 85 °
- 4. B (−8 − j6)
- 5. B (2∠−30°)
- 6. θ₄ = −90 °
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