For z₁ = −3 + j2 and z₂ = −6 − j4, find the real part of the product z₁·z₂.
Complex numbers worksheet with answers
1.Easy
z₁ = −3 + j2z₂ = −6 − j4
Re(z₁z₂) =
2.Easy
For z₁ = −7 + j5 and z₂ = −4 − j6, find the modulus of the quotient, |z₁/z₂|.
z₁ = −7 + j5z₂ = −4 − j6
|z₁/z₂| =
3.Medium
Write z = 3 − j7 in exponential form r·ejθ. Give θ in radians, between −π and π.
z = 3 − j7
θ = rad
4.Medium
The diagram shows z = 2 − j. With w = 0.5∠90°, click the point that represents z/w.
z = 2 − jw = 0.5∠90°
- 1A (4 − j2)
- 2B (−1 − j2)
- 3C (2 + j4)
- 4D (−2 − j4)
5.Hard
The equation z² − 8z + 25 = 0 has two complex roots. Find their modulus |z|.
p = −8q = 25
|z| =
6.Hard
One root of z³ − z² + 2 = 0 is z₁ = 1 + j. The coefficients are real. Find the real root r.
z₁ = 1 + j
r =
Answer key
- 1. Re(z₁z₂) = 26
- 2. |z₁/z₂| = 1.193
- 3. θ = −1.166 rad
- 4. D (−2 − j4)
- 5. |z| = 5
- 6. r = −1
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