For z₁ = −1 + j6 and z₂ = −2 + j6, find the real part of w = 3z₁ − 2z̄₂.
Complex numbers worksheet with answers
1.Easy
z₁ = −1 + j6z₂ = −2 + j6
Re(w) =
2.Easy
The Argand diagram shows z₁ = 5 + j. Click the point that represents j·z₁.
z₁ = 5 + j
- 1A (−1 + j5)
- 2B (−5 − j)
- 3C (5 − j)
- 4D (−1 − j5)
3.Medium
Given z₁ = 5∠125° and z₂ = 1.5∠80°, find the real part of w = z₁·z₂.
z₁ = 5∠125°z₂ = 1.5∠80°
Re(w) =
4.Medium
Find the argument θ of z = −4 − j8 in degrees, as the principal value between −180° and 180°.
z = −4 − j8
θ = °
5.Hard
Use De Moivre's theorem to find the imaginary part of z⁷ for z = 1 − j√3.
z = 1 − j√3n = 7
Im(z⁷) =
6.Hard
One root of z³ − z² − 20z + 50 = 0 is z₁ = 3 + j. The coefficients are real. Find the real root r.
z₁ = 3 + j
r =
Answer key
- 1. Re(w) = 1
- 2. A (−1 + j5)
- 3. Re(w) = −6.797
- 4. θ = −116.6 °
- 5. Im(z⁷) = −110.9
- 6. r = −5
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