For z₁ = −7 − j4 and z₂ = −4 + j, find the real part of the product z₁·z₂.
Complex numbers worksheet with answers
1.Easy
z₁ = −7 − j4z₂ = −4 + j
Re(z₁z₂) =
2.Easy
For z₁ = −2 − j3 and z₂ = −5 + j6, find the imaginary part of the product z₁·z₂.
z₁ = −2 − j3z₂ = −5 + j6
Im(z₁z₂) =
3.Medium
Write z = −7 + j2 in exponential form r·ejθ. Give θ in radians, between −π and π.
z = −7 + j2
θ = rad
4.Medium
The diagram shows z = −2 + j4. With w = 0.5∠90°, click the point that represents z/w.
z = −2 + j4w = 0.5∠90°
- 1A (2 + j)
- 2B (−4 + j8)
- 3C (8 + j4)
- 4D (−8 − j4)
5.Hard
Solve z² + 8z + 18.25 = 0. The roots are a ± jb; find the real part a.
p = 8q = 18.25
a =
6.Hard
The roots of zⁿ = w with n = 4 and w = 81∠0° are zk = R1/n∠((φ + 360°·k)/n), k = 0, 1, 2, 3. Find the real part of z₀.
w = 81∠0°n = 4k = 0
Re(z₀) =
Answer key
- 1. Re(z₁z₂) = 32
- 2. Im(z₁z₂) = 3
- 3. θ = 2.863 rad
- 4. C (8 + j4)
- 5. a = −4
- 6. Re(z₀) = 3
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