For z₁ = −6 + j7 and z₂ = 6 − j4, find the imaginary part of w = 3z₁ − 3z̄₂.
Complex numbers worksheet with answers
1.Easy
z₁ = −6 + j7z₂ = 6 − j4
Im(w) =
2.Easy
The Argand diagram shows z₁ = 4 + j3 and z₂ = −2 + j4. Click the point that represents z₁ + z₂.
z₁ = 4 + j3z₂ = −2 + j4
- 1A (6 − j)
- 2B (2 − j7)
- 3C (2 + j7)
- 4D (−6 + j)
3.Medium
Find the argument θ of z = −4 − j3 in degrees, as the principal value between −180° and 180°.
z = −4 − j3
θ = °
4.Medium
Given z₁ = 2.5∠125° and z₂ = 3∠80°, find the real part of w = z₁/z₂.
z₁ = 2.5∠125°z₂ = 3∠80°
Re(w) =
5.Hard
One root of z³ − 13z² + 65z − 125 = 0 is z₁ = 4 + j3. The coefficients are real. Find the real root r.
z₁ = 4 + j3
r =
6.Hard
Exactly one of the points A–D is a root of z⁴ = 16∠120°. Click it.
w = 16∠120°n = 4
- 1A (1∠30°)
- 2B (2∠−30°)
- 3C (2∠30°)
- 4D (2∠75°)
Answer key
- 1. Im(w) = 9
- 2. C (2 + j7)
- 3. θ = −143.1 °
- 4. Re(w) = 0.5893
- 5. r = 5
- 6. C (2∠30°)
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