For z₁ = 7 + j4 and z₂ = −6 + j5, find the imaginary part of w = 3z₁ − 2z₂.
Complex numbers worksheet with answers
1.Easy
z₁ = 7 + j4z₂ = −6 + j5
Im(w) =
2.Easy
For z₁ = −5 − j6 and z₂ = −3 + j3, find the real part of the product z₁·z₂.
z₁ = −5 − j6z₂ = −3 + j3
Re(z₁z₂) =
3.Medium
Given z₁ = 4∠−60° and z₂ = 3∠45°, find the argument θ of w = z₁·z₂ in degrees, between −180° and 180°.
z₁ = 4∠−60°z₂ = 3∠45°
θ = °
4.Medium
Write z = 2.5∠65° in rectangular form a + jb and give the imaginary part b.
r = 2.5θ = 65°
b =
5.Hard
Exactly one of the points A–D is a root of z⁴ = 81∠60°. Click it.
w = 81∠60°n = 4
- 1A (5.4∠−30°)
- 2B (3∠−75°)
- 3C (3∠−30°)
- 4D (3∠60°)
6.Hard
Use De Moivre's theorem to find the imaginary part of z⁷ for z = 2 + j2.
z = 2 + j2n = 7
Im(z⁷) =
Answer key
- 1. Im(w) = 2
- 2. Re(z₁z₂) = 33
- 3. θ = −15 °
- 4. b = 2.266
- 5. B (3∠−75°)
- 6. Im(z⁷) = −1024
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