For z₁ = −6 + j8 and z₂ = 4 − j, find the modulus of the product, |z₁z₂|.
Complex numbers worksheet with answers
1.Easy
z₁ = −6 + j8z₂ = 4 − j
|z₁z₂| =
2.Easy
For z₁ = 6 − j3 and z₂ = 4 − j6, find the imaginary part of w = −z₁ + 2z₂.
z₁ = 6 − j3z₂ = 4 − j6
Im(w) =
3.Medium
Given z₁ = 3∠150° and z₂ = 1.5∠20°, find the imaginary part of w = z₁·z₂.
z₁ = 3∠150°z₂ = 1.5∠20°
Im(w) =
4.Medium
The diagram shows z = 2 − j4. With w = 0.5∠−90°, click the point that represents z/w.
z = 2 − j4w = 0.5∠−90°
- 1A (2 + j)
- 2B (8 + j4)
- 3C (4 − j8)
- 4D (4 + j2)
5.Hard
The roots of zⁿ = w with n = 4 and w = 16∠0° are zk = R1/n∠((φ + 360°·k)/n), k = 0, 1, 2, 3. Find the real part of z₂.
w = 16∠0°n = 4k = 2
Re(z₂) =
6.Hard
Solve z² − 6z + 18 = 0. The roots are a ± jb; find the real part a.
p = −6q = 18
a =
Answer key
- 1. |z₁z₂| = 41.23
- 2. Im(w) = −9
- 3. Im(w) = 0.7814
- 4. B (8 + j4)
- 5. Re(z₂) = −2
- 6. a = 3
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