For z₁ = −6 + j and z₂ = −6 + j4, find the modulus of the product, |z₁z₂|.
Complex numbers worksheet with answers
1.Easy
z₁ = −6 + jz₂ = −6 + j4
|z₁z₂| =
2.Easy
The Argand diagram shows z₁ = −3 − j4. Click the point that represents z̄₁.
z₁ = −3 − j4
- 1A (3 + j4)
- 2B (3 − j4)
- 3C (−3 + j4)
- 4D (−4 − j3)
3.Medium
Write z = 7 − j5 in exponential form r·ejθ. Give θ in radians, between −π and π.
z = 7 − j5
θ = rad
4.Medium
The diagram shows z = 4 + j3. With w = 2∠−90°, click the point that represents z·w.
z = 4 + j3w = 2∠−90°
- 1A (6 − j8)
- 2B (8 + j6)
- 3C (−6 + j8)
- 4D (3 − j4)
5.Hard
Solve z² + 6z + 13 = 0. The roots are a ± jb; find the real part a.
p = 6q = 13
a =
6.Hard
Find the imaginary part of (1 + j)³.
z = 1 + jn = 3
Im(z³) =
Answer key
- 1. |z₁z₂| = 43.86
- 2. C (−3 + j4)
- 3. θ = −0.6202 rad
- 4. A (6 − j8)
- 5. a = −3
- 6. Im(z³) = 2
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