For z₁ = −1 − j5 and z₂ = −5 − j, find the imaginary part of the product z₁·z₂.
Complex numbers worksheet with answers
1.Easy
z₁ = −1 − j5z₂ = −5 − j
Im(z₁z₂) =
2.Easy
For z₁ = 7 − j3 and z₂ = −5 + j6, find the real part of the product z₁·z₂.
z₁ = 7 − j3z₂ = −5 + j6
Re(z₁z₂) =
3.Medium
Given z₁ = 1.5∠55° and z₂ = 1.5∠45°, find the imaginary part of w = z₁·z₂.
z₁ = 1.5∠55°z₂ = 1.5∠45°
Im(w) =
4.Medium
Write z = 8∠−75° in rectangular form a + jb and give the real part a.
r = 8θ = −75°
a =
5.Hard
Exactly one of the points A–D is a root of z⁴ = 16∠60°. Click it.
w = 16∠60°n = 4
- 1A (2∠−120°)
- 2B (2∠−165°)
- 3C (1∠−165°)
- 4D (2∠60°)
6.Hard
The roots of zⁿ = w with n = 3 and w = 27∠180° are zk = R1/n∠((φ + 360°·k)/n), k = 0, 1, 2. Find the imaginary part of z₀.
w = 27∠180°n = 3k = 0
Im(z₀) =
Answer key
- 1. Im(z₁z₂) = 26
- 2. Re(z₁z₂) = −17
- 3. Im(w) = 2.216
- 4. a = 2.071
- 5. B (2∠−165°)
- 6. Im(z₀) = 2.598
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